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Aether Geometry PDF Print E-mail
Written by David Thomson   
Sunday, 24 January 2010 13:41

Time and space have inherent geometry with respect to each other. We only see the spatial geometry of space because the matter that makes up our body and senses all has half spin (at the subatomic level). The half spin is due to physical matter, as we experience it, only occurring in the forward dimension of time.

Compared to space, time has a spherical geometry. If we could see spacetime through "God's" eyes, we would be able to see this spherical geometry of time. But even though we cannot directly see the geometry of spacetime in its full expression, we can see the effects of curved time with regard to space.

The information below is a quick treatment of the simple mathematics used to describe the geometry of time in two manifestations.

Assuming a unit circle with radius a:

we can plot the radius r as a function of q for both the positive and negative charges of Aether.


Two equations are used, each plotting one of the two circles. We run q from -π/2 to π/2. This is because π is the geometrical constant arising from the effect of time on 3D space and we only experience the forward half of time.

Making a figure of revolution out of the double circle yields a pair of spheres tangent at the origin.


We can also plot the radius r as a function of q for both the clockwise and counterclockwise spins of Aether.


Two equations are used, each plotting one of the two circles. We run q from -π/2 to π/2. In this instance it is because π has two directions of spin.

Making a figure of revolution out of the double circle yields a torus.

The double sphere represents the "surface of time", and the toroid represents the "surface of space". Time and space come together in the rmfd constant of the Aether.

rmfd (rotating magnetic field) constant of the Aether

The rmfd unit of Aether has a geometrical constant of 16π2. Both the spheres (4π x 4π) and the double loxodrome have surface constants of 16π2.

Special thanks to Tom Gutman for helping me to understand how to use MathCAD to produce the above images.

Last Updated on Sunday, 14 February 2010 16:24
 

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